Max Posted October 6, 2004 Share Posted October 6, 2004 If an amp is 1000w bridged-mono, does that mean that each channel will be 500w in stereo at 4ohms? And then i guess 250w per channel at 8ohmns? Quote Link to comment Share on other sites More sharing options...
Liam Posted October 6, 2004 Share Posted October 6, 2004 Depends on the amp mate, but I don't think you would expect the impedance to shift dramatically like that, if at all. Quote Link to comment Share on other sites More sharing options...
Max Posted October 6, 2004 Author Share Posted October 6, 2004 no, i did some research on it this afternoon since nobody responded. 1000w bridges mono is 500w per channel in stereo at 8 ohm and 250 per channel at 4 ohms Quote Link to comment Share on other sites More sharing options...
Max Posted October 6, 2004 Author Share Posted October 6, 2004 the impedance is in the speakers, not the amp. You get a higher output in watts with speakers that have 4ohms of resistance than you do with speakers than have 8ohm of resistance Quote Link to comment Share on other sites More sharing options...
Liam Posted October 6, 2004 Share Posted October 6, 2004 No, the impedance needs to be matched between the speakers and the amp for maximum power output. Trust me, read up on a little AC theory and it will all become clear. Quote Link to comment Share on other sites More sharing options...
Liam Posted October 6, 2004 Share Posted October 6, 2004 Also: an impedance is NOT a resistance. An impedance is analagous to resistance in DC, but it is not the same. Quote Link to comment Share on other sites More sharing options...
Max Posted October 6, 2004 Author Share Posted October 6, 2004 Regardless of our quarrel about impedance, the above breakdown of splitting the watts in an unbridges amp is 100% correct. If it's 1000w bridged, then unbridged it's 500w per channel at 4 ohms. Quote Link to comment Share on other sites More sharing options...
rygon Posted October 6, 2004 Share Posted October 6, 2004 using my little knowledge which has a) been gathered from the discovery channel and b) came to me whilst smokin sum shit. impedance is the sum of resistance against (reacatance - capacitance). On a graph you have resistance on the x axis and reactance and capacitance on the y axis (both being equally opposite. the sum of those give the impedance z = sqrt (r sq + (l - c)sq) and sadly enopugh i actually finds this stuff rather interesting (especially when i sumtimes even get this stuff right)....god im a geek readin on what liam sez yeh he is correct with that but then again it most prob doeant help you too much stickey although it is good to know Quote Link to comment Share on other sites More sharing options...
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